x^2/5-3x^1/5+2=0

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Solution for x^2/5-3x^1/5+2=0 equation: 


x in (-oo:+oo)

(x^2)/5-((3*x^1)/5)+2 = 0

(x^2)/5+(-3/5)*x+2 = 0

1/5*x^2-3/5*x+2 = 0

DELTA = (-3/5)^2-(1/5*2*4)

DELTA = -31/25

DELTA < 0

x belongs to the empty set

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